Capacitance

Capacitors:

(i) Capacitance Equation:

$$q \propto V \Rightarrow q = CV$$

  • $q$: Charge on positive plate of the capacitor

  • $C$: Capacitance of capacitor.

  • $V$: Potential difference between positive and negative plates.

(ii) Representation of capacitor:

(iii) Energy stored in the capacitor:

$$U = \frac{1}{2} CV^2 = \frac{Q^2}{2C} = \frac{QV}{2}$$

(iv) Energy density

$$ \text{Energy density }= \frac{1}{2} \varepsilon_0 \varepsilon_r E^2 = \frac{1}{2} \varepsilon_0 KE^2$$

  • $\varepsilon_r$: Relative permittivity of the medium.

  • $K = \varepsilon_r$: Dielectric Constant

  • For vacuum, energy density $= \frac{1}{2} \varepsilon_0 E^2$

(v) Types of Capacitors:

(a) Parallel plate capacitor

$$C = \frac{\varepsilon_0 \varepsilon_r A}{d} = K\frac{\varepsilon_0 A}{d}$$

  • $A$: Area of plates

  • $d$: distance between the plates ($\ll$ size of plate)

(b) Spherical Capacitor:

  • Capacitance of an isolated spherical Conductor (hollow or solid)

$$C = 4 \pi \varepsilon_0 \varepsilon_r R$$

$R$: Radius of the spherical conductor

  • Capacitance of spherical capacitor

$$C = 4 \pi \varepsilon_0 \frac{ab}{(b-a)} = \frac{4 \pi \varepsilon_0 K ab}{(b-a)}$$

(c) Cylindrical Capacitor:

$\ell \gg {a, b}$

Capacitance per unit length: $$\frac{C}{l}= \frac{2 \pi \varepsilon_0}{\ell \ln(b / a)} \text{F/m}$$

(vi) Capacitance of capacitor depends on:

(a) Area of plates

(b) Distance between the plates

(c) Dielectric medium between the plates.

(vii) Electric field intensity between the plates of capacitor:

$$E = \frac{\sigma}{\varepsilon_0} = \frac{V}{d}$$

$\sigma$: Surface charge density

(viii) Force experienced by any plate of capacitor:

$$F = \frac{q^2}{2A\varepsilon_0}$$

Distribution of Charges on Connecting Two Charged Capacitors:

When two capacitors $C_1$ and $C_2$ are connected as shown in the figure:

(a) Common potential:

$$V = \frac{C_1 V_1 + C_2 V_2}{C_1 + C_2} = \frac{\text{Total charge}}{\text{Total capacitance}}$$

(b) Capacitance Equation:

$$Q_1’ = C_1 V = \frac{C_1}{C_1 + C_2}(Q_1 + Q_2)$$

$$Q_2’ = C_2 V = \frac{C_2}{C_1 + C_2}(Q_1 + Q_2)$$

(c) Heat loss during redistribution:

$$\Delta H = U_i - U_f = \frac{1}{2} \frac{C_1 C_2}{C_1 + C_2}(V_1 - V_2)^2$$

The loss of energy is in the form of Joule heating in the wire.

Combination of Capacitor

(i) Series Combination:

$$\frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3}$$

$$V_1 : V_2 : V_3 = \frac{1}{C_1} : \frac{1}{C_2} : \frac{1}{C_3}$$

(ii) Parallel Combination:

$$C_{eq} = C_1 + C_2 + C_3$$

$$Q_1 : Q_2 : Q_3 = C_1 : C_2 : C_3$$

Charging and Discharging of a Capacitor:

(i) Charging of Capacitor (Capacitor initially uncharged):

$$q = q_0(1 - e^{-t / \tau})$$

  • $q_0$: Charge on the capacitor at steady state

  • $q_0 = CV$

  • $\tau$: Time constant $= CR_{eq}$

  • Current: $$I = \frac{q_0}{\tau} e^{-t / \tau} = \frac{V}{R} e^{-t / \tau}$$

(ii) Discharging of Capacitor:

$$q = q_0 e^{-t / \tau}$$

  • $q_0$: Initial charge on the capacitor

  • Current: $$I = \frac{q_0}{\tau} e^{-t / \tau}$$

Capacitor with Dielectric:

(i) Capacitance in the presence of dielectric:

  • Capacitance in the presence of dielectric: $$C = \frac{K \varepsilon_0 A}{d} = KC_0$$

  • $C_0$: Capacitance in the absence of dielectric.

(ii) Inside A Dielectric Material:

$$E_{in} = E - E_{ind} = \frac{\sigma}{\varepsilon_0} - \frac{\sigma_b}{\varepsilon_0} = \frac{\sigma}{K\varepsilon_0} \frac{V}{d}$$

$E: \frac{\sigma}{\varepsilon_0}$: Electric field in the absence of dielectric

$E_{ind}$: Induced (bound) charge density.

(iii) Relationship Between Bound Charge Density And Free Charge Density

$$\sigma_b = \sigma\left(1 - \frac{1}{K}\right).$$

Force on Dielectric:

(i) When the battery is connected:

$$F = \frac{\varepsilon_0 b(K - 1)V^2}{2d}$$

(ii) When the battery is not connected:

$$F = \frac{Q^2}{2 C^2} \frac{dC}{dx}$$

(iii) The force on the dielectric will be zero when the dielectric is fully inside.



sathee Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on

Please select your preferred language
कृपया अपनी पसंदीदा भाषा चुनें