Unit 8 The D And F Block Elements (Intext Questions-6)
Intext Question
8.8 Calculate the ‘spin only’ magnetic moment of $\mathrm{M}^{2+}{ _(a q)}$ ion $(Z=27)$.
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Answer
Electronic configuration of M atom with Z = 27 is $ [Ar] 3d^74s^2 $
Electronic configuration of $ M^{2+} $ will be $ [Ar] 3d^7 $
Thus , it has three unpaired electrons .
$ \therefore $ Spin only magnetic moment
$\mu=\sqrt{n(n+2)} B.M. $
where $n=$ number of unpaired electrons
Putting $\mathrm{n}=3$
we get, $\mu=\sqrt{3(3+2)} $
$ = \sqrt{15} B.M. $
$=3.87 \mathrm{BM}$
BETA
