Neet Solved Paper 2013 Question 37
Question: Nitrobenzene on reaction with cone. $ HNO _3/H _2SO _4 $ at $ 80-100{}^\circ C $ forms which one of the following products?
Options:
A) 1, 2-dinitrobenzene
B) 1, 3-dinitrobenzene
C) 1, 4-dinitrobenzene
D) 1, 2, 4-trinitrobenzene
Show Answer
Answer:
Correct Answer: B
Solution:
$ N{O_2} $ group being electron withdrawing reduces electron density at output positions. Hence, now the mete-position becomes electron rich on which the electrophone (nitronium ion) attacks during nitration.
$ HNO _3+H _2SO _4\xrightarrow[{}]{{}}H _2NO_3^{+}+HSO_4^{-} $ $ H _2O+\underset{electrophile}{\mathop{NO_4^{-}}}, $
BETA
