Neet Solved Paper 2013 Question 37
Question: For photoelectric emission from certain metal the cut-off frequency is v. If radiation of frequency 2v impinges on the metal plate, the maximum possible velocity of the emitted electron will be (m is the electron mass)
Options:
A) $ \sqrt{\frac{hv}{(2m)}} $
B) $ \sqrt{\frac{hv}{m}} $
C) $ \sqrt{\frac{2hv}{m}} $
D) $ \sqrt[2]{\frac{hv}{m}} $
Show Answer
Answer:
Correct Answer: C
Solution:
As $ \frac{1}{2}mv _{\max }^{2}=hv $
$ \Rightarrow $ $ v _{\max }^{2}=\frac{2hv}{m} $
$ \therefore $ $ {v _{\max }}=\sqrt{\frac{2hv}{m}} $
BETA
