NEET Solved Paper 2014 Question 9
Question: When $ 0.1mol,MnO_4^{2-} $ is oxidised, the quantity of electricity required to completely oxidise $ MnO_4^{2-} $ is $ MnO_4^{-} $ [AIPMT 2014]
Options:
A) 96500 C
B) $ 2\times 96500,C $
C) 9650C
D) 96.50 C
Show Answer
Answer:
Correct Answer: C
Solution:
$ \underset{(+7)}{\mathop{MnO_4^{2-}}},\underset{(+6)}{\mathop{MnO_4^{-}}}, $
As per the equation, for 1 mole of $ MnO_4^{2-} $ , 1 F of electricity is required.
Thus, for 0.1 mole of $ MnO_4^{2-} $ , 0.1 F of electricity is required.
Since, 1 F = 96500 C
$ \therefore $ $ 0.1F=0.1\times 96500C $ = 9650 C Hence, 9650 C of electricity is required to completely oxidise $ MnO_4^{2-} $ to $ MnO_4^{-} $ .
BETA
