NEET Solved Paper 2014 Question 15
Question: Steam at $ 100^{o}C $ is passed into 20 g of water at $ 10^{o}C $ . When water acquires a temperature of $ 80^{o}C $ , the mass of water present will be [Take specific heat of water = $ 1,cal{g^{-1}}{{,}^{{}^\circ }}{C^{-1}} $ and latent heat of steam $ =540cal{g^{-1}}] $ [AIPMT 2014]
Options:
A) 24g
B) 31.5g
C) 42.5g
D) 22.5g
Show Answer
Answer:
Correct Answer: D
Solution:
Heat lost by steam = Heat gained by water Let M? amount of heat converts into water.
$ m’\times L=ms,\Delta t $ $ m’\times 540=20\times 1\times (80-10) $ $ m’=\frac{20\times 70}{540}=2.5g $
Now, net water = 20 + 2.5 = 22.5g
BETA
