NEET Solved Paper 2014 Question 33
Question: A transformer having efficiency of 90% is working on 200 V and 3 kW power supply. If the current in the secondary coil is 6 A, the voltage across the secondary coil and the current in the primary coil respectively are [AIPMT 2014]
Options:
A) 300 V, 15 A
B) 450 V, 15 A
C) 450 V, 13.5 A
D) 600 V, 15 A
Show Answer
Answer:
Correct Answer: B
Solution:
Initial power = 3000 W As efficiency is 90% then
final power $ =3000\times \frac{90}{100} $ $ =2700W $
$ \Rightarrow $ $ . \begin{aligned} & V _1l _1=3000W \\ & V _1l _1=2700W \\ \end{aligned} ]……(i) $
So, $ V _2\frac{2700}{6}=\frac{900}{2}=450V $ and $ l _1\frac{3000}{200}=15A $
BETA
