Neet Solved Paper 2015 Question 17
Question: The two ends of a metal rod are maintained at temperatures $ {100^{o}}C $ and $ {110^{o}}C $ . The rate of heat flow in the rod is found to be 4.0 J/s. If the ends are maintained at temperatures $ {200^{o}}C $ and $ {210^{o}}C, $ the rate of heat flow will be
Options:
A) 44.0 J/s
B) 16.8 J/s
C) 8.0 J/s
D) 4.0 J/s
Show Answer
Answer:
Correct Answer: D
Solution:
Here, $ \Delta T _1=110-100={10^{{}^\circ }}C $
$ \frac{dQ _1}{dt}=4J/s $ $ \Delta T _2=210-200={10^{{}^\circ }}C $
$ \frac{dQ _2}{dt}=? $
As the rate of heat flow is directly proportional to the temperature difference and the temperature difference in both the cases is same
i.e. $ {10^{o}}C $ . So, the same rate of heat will flow in the second case.
Hence, $ \frac{dQ _2}{dt}=4J/s $
BETA
