Neet Solved Paper 2015 Question 27
Question: The electric field in a certain region is acting radially outward and is given by E = Ar. A. charge contained in a sphere of radius ‘a’ centred at the origin of the field’ will be given by
Options:
A) $ 4\pi {\varepsilon_0}Aa^{2} $
B) $ A{\varepsilon_0}a^{2} $
C) $ 4\pi {\varepsilon_0}Aa^{3} $
D) $ {\varepsilon_0}Aa^{3} $
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Answer:
Correct Answer: C
Solution:
Given, Here, r = a $ E=\frac{1}{4\pi {\varepsilon_0}}.\frac{q}{a^{2}} $
From Eq. (i), $ \frac{1}{4\pi {\varepsilon_0}}.\frac{q}{a^{2}}=Aa $
$ \Rightarrow q=4\pi {\varepsilon_0}Aa^{3} $
BETA
