Neet Solved Paper 2015 Question 43
Question: If radius of the $ _13^{27}Al $ nucleus is taken to be $ {R _{Al}}, $ then the radius of $ _53^{125}Te $ nucleus is nearly
Options:
A) $ {{( \frac{53}{13} )}^{\frac{1}{3}}}{R _{Al}} $
B) $ \frac{5}{3}{R _{Al}} $
C) $ \frac{3}{5}{R _{Al}} $
D) $ {{( \frac{13}{53} )}^{\frac{1}{3}}}{R _{Al}} $
Show Answer
Answer:
Correct Answer: B
Solution:
Radius of the nucleus is given by
$ R=R _0{A^{1/3}}\Rightarrow R\propto {A^{1/3}} $
$ \frac{{R _{Al}}}{R _{Te}}={{( \frac{{A _{Al}}}{A _{Te}} )}^{1/3}}={{( \frac{27}{125} )}^{1/3}}=\frac{3}{5} $
$ R _{Te}=\frac{5}{3}{R _{Al}} $
BETA
