NEET Solved Paper 2016 Question 32
Question: The ionic radii of $ {A^{+}} $ and $ {B^{}} $ ions are $ 0.98\times 10{{}^{10}}m $ and $ 1.81\times 10^{10}\text{ m}. $ The coordination number of each ion in AB is :-
Options:
A) 6
B) 4
C) 8
D) 2
Show Answer
Answer:
Correct Answer: A
Solution:
- $ \text{radio ratio = }\frac{{r _{+}}}{{r _{-}}}=\frac{0.98\times {10^{-10}}}{1.81\times {10^{-10}}}=0.54 $ radii ratio is in between 0.414 to 0.732 so, coordination number is 6
BETA
