NEET Solved Paper 2016 Question 23
Question: When an $ \alpha - $ particle of mass ’m’ moving with velocity ‘v’ bombards on a heavy nucleus of charge ‘Ze’, its distance of closest approach from the nucleus depends on m as :
Options:
A) $ \frac{1}{m} $
B) $ \frac{1}{\sqrt{m}} $
C) $ \frac{1}{m^{2}} $
D) m
Show Answer
Answer:
Correct Answer: A
Solution:
At closest distance of approach, the kinetic energy of the particle will convert completely into electrostatic potential energy.
$ \Rightarrow $ $ \frac{1}{2}mv^{2}=\frac{KQq}{d}\Rightarrow d\propto \frac{1}{m} $
BETA
