NEET Solved Paper 2017 Question 23
Question: A gas is allowed to expand in a well-insulated container against a constant external pressure of 2.5 atm from an initial volume of 2.50 L to a final volume of 4.50 L. The change in internal energy $ \Delta U $ of the gas in joules will be
Options:
A) +505 J
B) 1136.25 J
C) -500 J
D) -505 J
Show Answer
Answer:
Correct Answer: D
Solution:
- $ \Delta U=q+w $ For adiabatic process, q = 0
$ \therefore $ $ \Delta U=w $ $ =-P.\Delta V $ $ =-2.5\times 2,L-atm $ $ =-5\times 101.3,J $ $ =-506.5,J $ $ =-505,J $
BETA
