NEET Solved Paper 2018 Question 1
Question: The volume (V) of a monatomic gas varies with its temperature (T), as shown in the graph. The ratio of work done by the gas, to the heat absorbed by it, when it undergoes a change from state A to state B, is
Options:
A) $ \frac{1}{3} $
B) $ \frac{2}{3} $
C) $ \frac{2}{5} $
D) $ \frac{2}{7} $
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Answer:
Correct Answer: C
Solution:
- Given process is isobaric $ \text{dQ=n}{C_p}dT $ $ \text{dQ=n}( \frac{5}{2}R )dT $ $ \text{dW=PdV=nRdT} $
Required ratio $ \text{=}\frac{dW}{dQ}\text{=}\frac{nRdT}{n( \frac{5}{2}R )dT}\text{=}\frac{2}{5} $
BETA
