NEET Solved Paper 2018 Question 5
Question: A carbon resistor of $ (47\pm 4.7) $ $ k\Omega $ is to be marked with rings of different colours for its identification. The colour code sequence will be [NEET - 2018]
Options:
A) Yellow - Green - Violet - Gold
B) Yellow - Violet - Orange - Silver
C) Violet - Yellow - Orange - Silver
D) Green - Orange - Violet - Gold
Show Answer
Answer:
Correct Answer: B
Solution:
- $ (47\pm 4.7)k\Omega =47\times 10^{3}\pm 10% $
$ \therefore $ Yellow - Violet - Orange - Silver
BETA
