NEET Solved Paper 2019 Question 2
Question: For the chemical reaction $ N _2\text{(g)}+3H _2(g)\rightarrow 2NH _3( g ) $ [NEET 5-5-2019]
Options:
A) $ -\frac{d[N _2]}{dt}=\frac{1}{2}\frac{d[NH _3]}{dt} $
B) $ 3\frac{d[H _2]}{dt}=2\frac{d[NH _3]}{dt} $
C) $ -\frac{1}{3}\frac{d[H _2]}{dt}=-\frac{1}{2}\frac{d[NH _3]}{dt} $
D) $ -\frac{d[N _2]}{dt}=2\frac{d[NH _3]}{dt} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ N _2+3H _2\rightarrow 2NH _3 $
$ -\frac{dN _2}{dt}=-\frac{1}{3}\frac{dH _2}{dt}=+\frac{1}{2}-\frac{dNH _3}{dt} $
$ -\frac{dN _2}{dt}=+\frac{1}{2}\frac{d[NH _3]}{dt} $
BETA
