NEET Solved Paper 2019 Question 10
Question: An electron is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is, (nearly) $ (m _{e}=9\times 10^{31}kg) $ : [NEET 5-5-2019]
Options:
A) $ 12.2\times 10^{14}m $
B) 12.2 nm
C) $ 12.2\times 10^{13}m $
D) $ 12.2\times 10^{12}m $
Show Answer
Answer:
Correct Answer: D
Solution:
$ \lambda =\frac{12.27}{\sqrt{V}}\overset{o}{\mathop{A}},=\frac{12.27}{\sqrt{10,000}}\overset{o}{\mathop{A}}, $
$ =12.27\times 10^{2}\overset{o}{\mathop{A}}, $
$ =12.27\times 10^{12}m $
BETA
